步進馬達轉速控制問題

log4518

使用L293D Quad Half-H Drivers 控制 4-Phase / 12 Volt Unipolar Stepper Motor \

以下為程式碼 (控制正轉，越來越快)
' {$STAMP BS2}
' {$PBASIC 2.5}
PotCW PIN 0 ' clockwise pot input
PotCCW PIN 1 ' counter-cw pot input
Coils VAR OUTB ' output to stepper coils
' -----[ Constants ]-------------------------------------------------------
NumSteps CON 4 ' use 4-step sequence
' -----[ Variables ]-------------------------------------------------------
idx VAR Byte ' loop counter
stpIdx VAR Nib ' step pointer
stpDelay VAR Byte ' delay for speed control
' -----[ EEPROM Data ]-----------------------------------------------------
' __
' ABAB
' -----
Step1 DATA %1100
Step2 DATA %0110
Step3 DATA %0011
Step4 DATA %1001
' -----[ Initialization ]--------------------------------------------------
Setup:
DIRB = %1111 ' make P4..P7 outputs
stpDelay = 1 ' set step delay
MAIN:
FOR idx = 1 TO 48 ' 1 rev forward
GOSUB Step_Fwd
PAUSE 80
NEXT
FOR idx = 1 TO 48 ' 1 rev forward
GOSUB Step_Fwd
PAUSE 60
NEXT
FOR idx = 1 TO 48 ' 1 rev forward
GOSUB Step_Fwd
PAUSE 40
NEXT
FOR idx = 1 TO 48 ' 1 rev forward
GOSUB Step_Fwd
PAUSE 20
NEXT
FOR idx = 1 TO 48 ' 1 rev forward
GOSUB Step_Fwd
PAUSE 5
NEXT
END
Step_Fwd:
stpIdx = stpIdx + 1 // NumSteps ' point to next step
GOTO Do_Step
Do_Step:
READ (Step1 + stpIdx), Coils ' output new coil data
PAUSE 10 ' pause between steps
RETURN


利用更改pause的數值來控制步進馬達
假如調太低 目進馬達會跟不到 造成在原地跳動的情形
請問該如何解決？

log4518

請問每一步都要很準嗎？
如果把八步或十六步當成一步來走
而去延長每八步或每十六步的間隔時間
這樣做可 ...
nichal 發表於 2010-11-6 13:35

請問如何將 八步或十六步  當一步來走呢？